how many prime brian shaws would be needed to

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Anon09/17/26, 08:08No.77521465

just 2 if you make one big enough

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Anon09/17/26, 15:33No.77521946

It depends on where on the planet it is going to strike

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Anon09/17/26, 15:54No.77521991

fuck you and your tiktok ecelebs

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Anon09/17/26, 15:56No.77521998

shaw not being in his prime is the actual hypothetical here. the asteroid means fuck all

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Anon09/18/26, 12:46No.77523539

32 years on this earth and I just learn of this asteroid's name

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Anon09/18/26, 13:39No.77523586

Oh boy a schizo thread

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Anon09/18/26, 14:48No.77523650

Back-of-the-envelopeAssume:Asteroid diameter: 10 km Density: ~3,000 kg/m3 Mass: ~1.6 × 1015 kg Velocity: 20,000 m/sIts momentum would therefore be roughly:3.2 × 1019 kg·m/sNow give each prime Brian Shaw an absurdly generous 10,000 N of sustained stopping force for one second.That's an impulse of:10,000 N·s per ShawSo:3.2 × 1019 ÷ 104 ≈ 3.2 × 1015 Brian ShawsSo: about 3 quadrillion prime Brian Shaws.

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Anon09/19/26, 10:53No.77524916

Just one.

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Anon09/19/26, 12:55No.77525026

1 Brian Shaw, traveling at 99% the speed of light, contacting the asteroid a light year before it reaches Earth

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Anon09/20/26, 09:42No.77526408

About tree fiddy

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