Anon05/12/26, 22:08No.16975155
Consider: A man with an initial mass of 70 kg produces a particularly extensive flatus with a total mass of 1 g at an anal exit velocity of 3 m/s. Following from the Tsiolkovsky equation, assuming a maximally directed propellant:
[math]\Delta v = v_e \ln \left(\frac{m_i}{m_f}\right)[/math]
This works out to a change of velocity of 4.3 μm/s per flatus.