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Anonymous10/04/25, 20:56No.16806282
>holds a gun to your head
Divide by zero. NOW.
86
Replies
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Anon10/04/25, 21:13No.16806294
Obviously infinity.
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Anon10/04/25, 22:00No.16806314
Doesn't really make a difference. I'll let him pull the trigger and spare the city
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Anon10/04/25, 22:03No.16806315
The calculator says no.
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Anon10/04/25, 22:12No.16806318
Err.0
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Anon10/04/25, 22:19No.16806319
Horseshoe theory. Zero is unsigned. Likewise, infinity is unsigned.
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Anon10/04/25, 22:37No.16806332
>Divide by zero. NOW.
Okay. 0^0=1. Since x^0=x/x, I just divided by zero.
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Anon10/05/25, 05:12No.16806530
Okay, I arbitrarily define x/0 = 0, and I say there is a remainder of x.
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Anon10/05/25, 09:48No.16806627
which zero? define its size.
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Anon10/05/25, 10:38No.16806649
the proof that broke /pol/
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Anon10/05/25, 10:49No.16806652
easy, 1/0=inf, 1/inf=0, and 0*inf=inf*0=stop being a fucking nigger
https://en.wikipedia.org/wiki/Extended_real_number_line
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Anon10/05/25, 23:36No.16807321
Q. WHAT IF INFINITY AND ZERO ARE EFFECTIVELY THE SAME NUMBER? OR 'INFINITY' IS SIMPLY NEGATIVE ZERO?
>the equations give the same result if your treat them as identical
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Anon10/06/25, 00:19No.16807356
Positive infinity
You shouldn’t assume field operations are consistent outside of it
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Anon10/06/25, 03:49No.16807481
(1/2) / (1/0)
=> (1/2) * (0/1)
=> 0/2
=> 0
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Anon10/06/25, 05:30No.16807512
I got everything and nothing here
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Anon10/07/25, 11:45No.16808578
>Divide by zero. NOW.
Ok. 5/0.
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Anon10/11/25, 02:45No.16811721
cannot do it. shoot the calculator.
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Anon10/11/25, 15:09No.16812038
why isn't it regarded as a no-op and treated like the operation never happened in the first place? how would that break mathematics?
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Anon10/12/25, 18:13No.16813153
Does anybody know how to divide by 0 on an abacus? I can't actually set the board starting state.
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Anon10/13/25, 06:35No.16813646
1/0 = undefined
1/-0 = -undefined
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Anon10/13/25, 07:14No.16813663
There's nothing to divide by
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Anon10/13/25, 22:37No.16814438
0/0 = 0
problem ?
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Anon10/14/25, 04:12No.16815732
5/0 = 5
This is because when you divide by 0, no division occurs so you are left with the same value you started with. You cannot prove this wrong
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Anon10/14/25, 13:59No.16816014
Take something and divide it nothing times. The question doesn't make sense and is why it's undefined.
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Anon10/14/25, 22:15No.16816670
Hehe[math]0 = 0+\varepsilon[/math]
[math]0/0 = (0+\varepsilon)/(0+\varepsilon)[/math]
[math]0/0 = \varepsilon/\varepsilon=1[/math]
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Anon10/16/25, 16:35No.16818397
ask me to make a triangle have only 2 sides and break the pythagorean theorem first
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Anon10/18/25, 20:52No.16820291
I would divide by x and then take the limit when x tends to 0
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Anon10/19/25, 00:20No.16820396
Undefined
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Anon10/19/25, 01:08No.16820433
I did: it turned my real numbers into a set with a single element. Are you happy?